Question:medium

An engine of power \( 58.8 \) kW pulls a train of mass \( 2 \times 10^5 \) kg with a velocity of \( 36 \text{ km h}^{-1} \). The coefficient of friction is

Show Hint

For constant speed: Power = friction force × velocity.
Updated On: May 2, 2026
  • $0.3$
  • $0.03$
  • $0.003$
  • $0.0003$
  • $0.04$
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0

Top Questions on work, energy and power

Questions Asked in KEAM exam