Question:medium

An emf of 2.8 mV is induced in a rectangular loop of area 150 cm$^2$ when the current in the loop changes from 3 A to 8 A in a time of 0.2 s. Then the self-inductance of the loop is

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The formula for self-induced EMF is $\mathcal{E} = -L \frac{dI}{dt}$. Don't get confused by extra information provided in the problem, such as the area of the loop, which would be relevant for calculating mutual inductance or magnetic flux, but not self-inductance from EMF and current change.

Updated On: Mar 30, 2026

112 $\mu$H
56 $\mu$H
28 $\mu$H
84 $\mu$H

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The Correct Option is A

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