Question

An electron moving with velocity \( 2 \times 10^{-7} \, \text{m/s} \), describes a circle in a magnetic field of strength \( 2 \times 10^{-2} \, \text{T} \). If \( \frac{e}{m} \) of the electron is \( 1.76 \times 10^{11} \, \text{C/kg} \), then the diameter of the circle will be:

• A. 11 cm
• B. 1.1 cm
• C. 1.1 m
• D. 1.1 mm

Hint:

The diameter of the circular path depends on the velocity, magnetic field strength, and the electron's charge-to-mass ratio.

Answer 1

The Correct Option is B