An electron moving along a straight line with a velocity of $6.4 \times 10^7 ms^{-1}$ is subjected to a magnetic field of 3 mT. If the magnetic field is applied perpendicular to the direction of the initial path of the electron, then the radius of the circular path in which the electron moves under the influence of the magnetic field is
(Mass of electron $= 9 \times 10^{-31}$ kg and charge of the electron $= 1.6 \times 10^{-19}$ C)
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Centripetal force is provided by magnetic Lorentz force: $\frac{mv^2}{r} = qvB \Rightarrow r = \frac{mv}{qB}$.