Question:easy

An electric lamp connected in series with a capacitor and an a.c source is glowing with certain brightness. On reducing the frequency of source the brightness of the lamp

Show Hint

Capacitive reactance is 1/(omega C), which rises when frequency falls.
Updated On: Oct 1, 2026
  • is increased
  • is reduced
  • remain the same
  • becomes zero
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Reactance
$X_C \propto 1/f$, so lowering $f$ raises $X_C$.

Step 2: Current
Impedance goes up, so $I$ goes down.

Step 3: Answer
Dimmer lamp, option (B).

Final Answer:
Option (B). \[ \boxed{\text{Reduced}} \]
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