Question:medium
An electric dipole of dipole moment \(12\mu \text{ C m}\) is suspended in a uniform electric field of intensity \(10^6 \text{Vm}^{-1}\). The work done in rotating it from \(0^\circ\) to \(60^\circ\) with respect to the field direction is
An electric dipole of dipole moment \(12\mu \text{ C m}\) is suspended in a uniform electric field of intensity \(10^6 \text{Vm}^{-1}\). The work done in rotating it from \(0^\circ\) to \(60^\circ\) with respect to the field direction is
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Always check the powers of 10. Here, \(\mu (10^{-6})\) and the field (\(10^6\)) cancel each other out perfectly, simplifying the calculation to just the dipole moment and the cosine difference.
Updated On: Jun 24, 2026
- 3 J
- 6 J
- 1.5 J
- 12 J
- 2 J
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The Correct Option is B
Solution and Explanation
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