An air bubble rises from the bottom of a lake of depth \(37\) m. The temperature of the lake is constant from the bottom to the top and atmospheric pressure is equal to the pressure due to \(10\) m of water column. The percentage increase in the volume of the bubble when it rises from a depth of \(20\) m to a depth of \(15\) m is
Show Hint
For an isothermal process,
\[
\boxed{PV=\text{constant}.}
\]
Pressure at a depth \(h\) in water is
\[
\boxed{P=P_{\text{atm}}+\rho gh.}
\]
When atmospheric pressure is expressed as an equivalent water column, simply add the corresponding height.