Question:medium

An aeroplane is moving in a circular path with a speed of 450 Kmph. What is the change in velocity in half revolution?

Show Hint

Change in speed is 0, but change in velocity is $2v$ for a $180^{\circ}$ turn.
  • 0 Kmph
  • 450 Kmph
  • 250 Kmph
  • 900 Kmph
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Velocity is a vector quantity, meaning it has both magnitude (speed) and direction. In circular motion, even if the speed remains constant, the direction changes continuously. After a half revolution, the object is moving in the exactly opposite direction.
Step 2: Key Formula or Approach:
1. Let the initial velocity be \(\vec{v}_1 = v\).
2. After half a revolution, the final velocity is \(\vec{v}_2 = -v\).
3. Change in velocity \(\Delta \vec{v} = \vec{v}_2 - \vec{v}_1\).
Step 3: Detailed Explanation:
Given speed \(v = 450\) Kmph. At the start of the half revolution, let the velocity be \(+450\) Kmph (in one direction). After half a revolution, the aeroplane is headed in the opposite direction, so the velocity is \(-450\) Kmph. Magnitude of change in velocity: \[ |\Delta v| = |v_{final} - v_{initial}| \] \[ |\Delta v| = |-450 - 450| \] \[ |\Delta v| = |-900| = 900 \text{ Kmph} \]
Step 4: Final Answer:
The change in velocity is 900 Kmph.
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