Comprehension

An ac voltage \(V_i = 12 sin (100 \pi t)V\) is applied between points A and B in a network of two ideal diodes and three resistors as shown in figure. During the positive half-cycle of the input voltage Vi supplied to the network.

Question: 1

Identify which of the two diodes will conduct and why ?

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For an ideal diode: \[ \boxed{ \text{Forward biased} \Rightarrow \text{Conducts} } \] \[ \boxed{ \text{Reverse biased} \Rightarrow \text{Does not conduct} } \] Always compare the potentials of the anode and cathode to determine whether a diode is ON or OFF.

Updated On: Jul 2, 2026

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Solution and Explanation

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Question: 2

Redraw an equivalent circuit diagram to show the flow of current.

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For an ideal diode: \[ \boxed{ \text{ON} \Rightarrow \text{Short circuit} } \] \[ \boxed{ \text{OFF} \Rightarrow \text{Open circuit} } \] Always redraw the circuit after replacing the conducting and non-conducting diodes.

Updated On: Jul 2, 2026

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Question: 3

Calculate the output voltage drops \(V_0\) across the three resistors when the input voltage attains its peak value.

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After replacing ideal diodes by short or open circuits, simplify the resistor network first. Then apply \[ V=IR \] to calculate the voltage drop across each resistor. Remember that resistors connected in parallel have the same potential difference across them.

Updated On: Jul 2, 2026

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