Question:medium

Ammonium ion (NH\textsubscript{4}\textsuperscript{+}) reacts with nitrite ion (NO\textsubscript{2}\textsuperscript{--}) in aqueous solution according to the equation
NH\textsubscript{4\textsuperscript{+}(aq) + NO\textsubscript{2}\textsuperscript{--}(aq) \(\rightarrow\) N\textsubscript{2}(g) + 2H\textsubscript{2}O(l)

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If doubling the concentration doubles the rate, the order is 1. If doubling the concentration quadruples the rate, the order is 2. Quick mental ratios are the key to solving these table-based questions in seconds!

Updated On: May 6, 2026

rate = \(k\) [NH\textsubscript{4}\textsuperscript{+}] [NO\textsubscript{2}\textsuperscript{--}]\textsuperscript{4}
rate = \(k\) [NH\textsubscript{4}\textsuperscript{+}] [NO\textsubscript{2}\textsuperscript{--}]
rate = \(k\) [NH\textsubscript{4}\textsuperscript{+}] [NO\textsubscript{2}\textsuperscript{--}]\textsuperscript{2}
rate = \(k\) [NH\textsubscript{4}\textsuperscript{+}]\textsuperscript{2} [NO\textsubscript{2}\textsuperscript{--}]
rate = \(k\) [NH\textsubscript{4}\textsuperscript{+}]\textsuperscript{1/2} [NO\textsubscript{2}\textsuperscript{--}]\textsuperscript{1/4}