Problem breakdown:
Amal buys \( x \) pens at 8 rupees each, for a total cost of \( 8x \) rupees. He also pays an employee a fixed wage \( W \).
He sells 100 pens at 12 rupees each, generating a revenue of \( 100 \times 12 = 1200 \) rupees.
Remaining pens: \( x - 100 \).
Revenue from remaining pens: \( 11(x - 100) \) rupees.
Total revenue: \( 1200 + 11(x - 100) \) rupees.
Net profit: Total revenue - Total cost - Wage = 300 rupees.
Equation: \( 1200 + 11x - 1100 - 8x - W = 300 \)
Simplified equation: \( 3x - W = 200 \quad \text{...(i)} \)
Revenue from remaining pens: \( 9(x - 100) \) rupees.
Total revenue: \( 1200 + 9(x - 100) \) rupees.
Net loss: Total cost + Wage - Total revenue = 300 rupees.
Equation: \( 8x + W - (1200 + 9x - 900) = 300 \)
Simplified equation: \( -x + W = 400 \quad \text{...(ii)} \)
Adding equations (i) and (ii):
\( (3x - W) + (-x + W) = 200 + 400 \)
Simplifying: \( 2x = 600 \)
Solving for \( x \): \( x = 300 \)
Substitute \( x = 300 \) into equation (i):
\( 3(300) - W = 200 \)
Simplifying: \( 900 - W = 200 \)
Solving for \( W \): \( W = 700 \)
The employee's wage is 700 rupees.
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