Step 1: Identify the complex formed.
In acidified aqueous solution, Al\(^{3+}\) coordinates six water molecules to give [Al(H\(_2\)O)\(_6\)]\(^{3+}\) with coordination number 6.
Step 2: Assign hybridisation.
Six bonds in an octahedral arrangement require one s + three p + two d orbitals = sp\(^3\)d\(^2\).
\[ \boxed{sp^3d^2} \]