Alternating current of peak value $(\frac{2}{π})$ A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1H. The peak value of induced e.m.f. in the secondary coil is
(Frequency of a.c. = 50 Hz)

Question

In an a.c. circuit, voltage and current are given by: \[ V = 100 \sin(100t) \, \text{V} \quad \text{and} \quad I = 100 \sin\left(100t + \frac{\pi}{3}\right) \, \text{mA}. \] The average power dissipated in one cycle is:

Answer 1

Step 1: Quick calculation
Peak rate of change of current is $2\pi f I_0 = 2\pi(50)\frac2\pi = 200\ \text{A/s}$.

Step 2: Multiply by M
$M = 1$ H gives $200$ V. Option (C).

Final Answer:
200 V. \[ \boxed{\text{(C)}\ 200\ \text{V}} \]

Alternating current of peak value \((\frac{2}{π})\) A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1H. The peak value of induced e.m.f. in the secondary coil is
(Frequency of a.c. = 50 Hz)

Show Hint

The Correct Option is C

Solution and Explanation

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Alternating current of peak value \((\frac{2}{π})\) A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1H. The peak value of induced e.m.f. in the secondary coil is(Frequency of a.c. = 50 Hz)