Question:medium

Air enters an adiabatic nozzle at 300 kPa and 500 K with a velocity of 10 m/s. It leaves the nozzle at 100 kPa with a velocity of 180 m/s. The specific heat of air \(C_{\text{p}} = 1008\text{ J/kg}\cdot\text{K}\). The exit temperature of air is

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Always ensure units are consistent.
Velocity squared ($V^2$) yields units of $\text{m}^2/\text{s}^2$, which is equivalent to $\text{J/kg}$.
Using $C_{\text{p}}$ in $\text{J/kg}\cdot\text{K}$ (rather than $\text{kJ/kg}\cdot\text{K}$) ensures correct dimensional consistency without conversion errors.
Updated On: Jul 9, 2026
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The Correct Option is C

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