Acid strength increases in the order given as
$HF < < HCl < < HBr < < HI$.
As the size of the elements $F, Cl, Br, I$ increases down the group, the bond strength of $HF, HCl, HBr$ and $HI$ decreases and so the acid strength increases.
In the light of the above statements, choose the correct answer from the options given below.
Statement I is incorrect but Statement II is true.
Show Solution
The Correct Option isA
Solution and Explanation
To determine the validity of the given statements regarding the strength of acids HF, HCl, HBr, and HI, let's analyze both statements separately:
Statement I: Acid strength increases in the order given as \(HF \ll HCl \ll HBr \ll HI\).
The acid strength of hydrides of halogens (HF, HCl, HBr, HI) increases as we move down the group in the periodic table.
Acid strength is inversely related to bond strength; weaker bonds dissociate more easily, making the acid stronger.
Going down the group, the size of the halogen atom increases (F < Cl < Br < I), leading to weaker H-X bonds because the bond length increases.
Thus, HI has the weakest bond and is the strongest acid, and HF has the strongest bond, making it the weakest acid in this group.
This statement is correct.
Statement II: As the size of the elements \(F, Cl, Br, I\) increases down the group, the bond strength of \(HF, HCl, HBr\), and \(HI\) decreases and so the acid strength increases.
This statement explains that the primary factor affecting acid strength in this context is the bond strength between the hydrogen atom and the halogen.
As the size of the halogen increases down the group, the H-X bond becomes weaker due to increased bond length, leading to easier dissociation.
This results in increased acid strength as the halogen size increases, precisely corroborating the stated order of increasing acid strength.
This statement is also correct.
Hence, the correct answer is: Both Statement I and Statement II are true.