Exams
Subjects
Classes
Home
Exams
Chemistry
Acids and Bases
accepting the definition ...
Question:
medium
Accepting the definition that an acid is a proton donor, the acid in the following reaction
\[ NH_3 + H_2O \rightleftharpoons NH_4^+ + OH^- \]
is
Show Hint
Water can act as an acid in some reactions by donating a proton.
JEECUP - 2024
JEECUP
Updated On:
Jan 15, 2026
OH\(^{-}\)
NH\(_4^+\)
H\(_2\)O
NH\(_3\)
Show Solution
The Correct Option is
C
Solution and Explanation
According to the Bronsted-Lowry definition, water (\(H_2O\)) donates a proton to ammonia (\(NH_3\)), acting as an acid.
Download Solution in PDF
Was this answer helpful?
0
Top Questions on Acids and Bases
What is the pH of a 0.01 M hydrochloric acid (HCl) solution?
MHT CET - 2024
Chemistry
Acids and Bases
View Solution
Which of the following is the strongest acid?
MHT CET - 2025
Chemistry
Acids and Bases
View Solution
What is the pH of a 0.001 M NaOH solution?
MHT CET - 2025
Chemistry
Acids and Bases
View Solution
What is the pH of a 0.01 M solution of hydrochloric acid (HCl)?
MHT CET - 2025
Chemistry
Acids and Bases
View Solution
Want to practice more? Try solving extra ecology questions today
View All Questions
Questions Asked in JEECUP exam
The perimeter of an equilateral triangle whose area is \( 4\sqrt{3} \, \text{cm}^2 \) is equal to:
JEECUP - 2024
Triangles
View Solution
\(\tan 3A - \tan 2A \cdot \tan A\) is equal to:
JEECUP - 2024
Trigonometric Identities
View Solution
The value of \( \sqrt[3]{72.9} \) is:
JEECUP - 2024
Cube Roots
View Solution
If 7 is the mean of 5, 3, 0.5, 4.5, \( a \), 8.5, 9.5, then the value of \( a \) is:
JEECUP - 2024
Arithmetic Mean
View Solution
The value of \( \sin \theta + \cos(90^\circ + \theta) + \sin(180^\circ - \theta) + \sin(180^\circ + \theta) \) is:
JEECUP - 2024
Trigonometry
View Solution