Question:medium

A wire of length 4.4 m is bent round in the shape of a circular loop and carries a current of 1.0 A. The magnetic moment of the loop will be:

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The magnetic moment of a circular loop is the product of the current and the area. Use the circumference to find the radius of the loop.
Updated On: Jan 13, 2026
  • \( 0.7 \, \text{Am}^2 \)
  • \( 1.54 \, \text{Am}^2 \)
  • \( 2.10 \, \text{Am}^2 \)
  • \( 3.5 \, \text{Am}^2 \)
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The Correct Option is B

Solution and Explanation

The magnetic moment \( M \) of a current-carrying loop is defined as \( M = I A \), where \( I \) is the current and \( A \) is the loop's area. For a circular loop, the area is \( A = \pi r^2 \). Given a circumference of \( 2\pi r = 4.4 \, \text{m} \), the radius is calculated as \( r = \frac{4.4}{2\pi} = 0.7 \, \text{m} \). Consequently, the area is \( A = \pi (0.7)^2 = 1.54 \, \text{m}^2 \). Therefore, the magnetic moment is \( M = 1.0 \times 1.54 = 1.54 \, \text{Am}^2 \).
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