Question:medium

A 1 cm straight segment of a conductor carrying 1 A current in \( x \)-direction lies symmetrically at the origin of Cartesian coordinate system. The magnetic field due to this segment at point (1m, 1m, 0) is:

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The Biot-Savart law provides a way to calculate the magnetic field produced by a current-carrying element.
Updated On: Sep 16, 2026
  • \( 1.0 \times 10^{-9} \, \text{T} \)
  • \( -1.0 \times 10^{-9} \, \text{T} \)
  • \( \frac{5.0}{\sqrt{2}} \times 10^{-10} \, \text{T} \)
  • \( -\frac{5.0}{\sqrt{2}} \times 10^{-10} \, \text{T} \)
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The Correct Option is C

Solution and Explanation

1. Setup Definition:

  • Conductor length: 1 cm (0.01 m), centered at origin along x-axis, from \( -0.005\,\text{m} \) to \( +0.005\,\text{m} \).
  • Current: \( I = 1\,\text{A} \)
  • Observation point: \( (1, 1, 0) \)

2. Magnetic Field Calculation (Finite Segment):

Employing the Biot–Savart law for a finite straight conductor:

\[ \vec{B} = \frac{\mu_0 I}{4\pi r} (\sin\theta_1 + \sin\theta_2)\hat{n} \]

Parameters:

  • \( \mu_0 = 4\pi \times 10^{-7} \, \text{Tm/A} \) (permeability of free space)
  • \( r \) = perpendicular distance from wire to point = \( \sqrt{(1)^2 + (1)^2} = \sqrt{2} \, \text{m} \)
  • Due to symmetry, \( \theta_1 = \theta_2 \), angles measured from the wire's center to its ends.
  • \( \tan\theta = \frac{L/2}{r} = \frac{0.005}{\sqrt{2}} \Rightarrow \theta \approx \tan^{-1}(0.0035) \approx 0.2^\circ \) (negligibly small)
  • For small angles, \( \sin\theta \approx \theta \text{ (in radians)} \), thus \( \sin\theta_1 + \sin\theta_2 \approx 2\theta \)

Approximate magnetic field magnitude:

\[ B = \frac{4\pi \times 10^{-7} \times 1}{4\pi \times \sqrt{2}} \times 2 \times \frac{0.005}{\sqrt{2}} = \frac{10^{-7} \cdot 2 \cdot 0.005}{2} = \frac{10^{-7} \cdot 0.005}{\sqrt{2}} = \frac{5.0 \times 10^{-10}}{\sqrt{2}} \, \text{T} \]

3. Conclusion:

Option (C) \( \frac{5.0 \times 10^{-10}}{\sqrt{2}} \, \text{T} \) is the correct magnetic field value.

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