To solve the problem, we need to understand the phenomenon of electromagnetic induction in a rotating wire loop placed in a magnetic field. The induced electromotive force (EMF) in the loop is governed by Faraday's law of electromagnetic induction, which states that the induced EMF is proportional to the rate of change of magnetic flux through the loop.
The EMF can be expressed as:
E = -\frac{d\phi}{dt}
where \phi is the magnetic flux.
When a wire loop is rotated in a uniform magnetic field, the magnetic flux changes as a function of the angle of rotation. The flux is given by:
\phi = B \cdot A \cdot \cos(\theta)
where:
As the loop rotates through 360°, the direction of the magnetic flux relative to the loop changes, inducing an EMF. Every 180° of rotation, the direction of the magnetic flux changes, causing a change in the direction of the induced current. Therefore, the direction of the induced EMF (and hence the direction of the current) changes twice per revolution.
Let's analyze each option:
Therefore, the correct answer is that the direction of the induced EMF changes twice per revolution.
In a uniform magnetic field of \(0.049 T\), a magnetic needle performs \(20\) complete oscillations in \(5\) seconds as shown. The moment of inertia of the needle is \(9.8 \times 10 kg m^2\). If the magnitude of magnetic moment of the needle is \(x \times 10^{-5} Am^2\); then the value of '\(x\)' is
