Question:medium

A vector \( \mathbf{a} \) makes equal angles with all the three axes. If the magnitude of the vector is \( 5\sqrt{3} \) units, then find \( \mathbf{a} \).

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A vector making equal angles with all axes has direction cosines \( \frac{1}{\sqrt{3}} \). Multiply by the magnitude to find the vector components.
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Solution and Explanation

To determine the vector \( \mathbf{a} \), given that it forms equal angles with the three coordinate axes and possesses a magnitude of \( 5\sqrt{3} \) units.

1. Direction Cosines:
A vector that forms equal angles with the x-, y-, and z-axes has equal direction cosines. Let \( l \) represent this common direction cosine.

The property that the sum of the squares of direction cosines equals 1 yields:
\[l^2 + l^2 + l^2 = 1 \Rightarrow 3l^2 = 1 \Rightarrow l^2 = \frac{1}{3} \Rightarrow l = \frac{1}{\sqrt{3}}\]

2. Unit Vector:
The unit vector aligned with \( \mathbf{a} \) is:
\[\hat{\mathbf{a}} = \left\langle \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}} \right\rangle\]

3. Scalar Multiplication:
Multiplying the unit vector by the given magnitude \( 5\sqrt{3} \) results in:
\[\mathbf{a} = 5\sqrt{3} \cdot \left\langle \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}} \right\rangle = \left\langle 5, 5, 5 \right\rangle\]

Result:
The vector \( \mathbf{a} \) is \( \boxed{\langle 5, 5, 5 \rangle} \.

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