Question

A uniformly charged semicircular arc of radius $r$ has linear charge density $\lambda$. The electric field at its centre is $(\varepsilon_0 =$ permittivity of free space$)$

• A. $\dfrac{\lambda}{\varepsilon_0}$
• B. $\dfrac{2\varepsilon_0}{\lambda}$
• C. $\dfrac{\lambda}{4\pi\varepsilon_0 r}$
• D. $\dfrac{2\pi\varepsilon_0}{\lambda}$

Hint:

Physics Tip : For arc charge distributions, use symmetry to cancel opposite components.

Answer 1

The Correct Option is C