A uniform rod of length $1$ m and mass of $2$ kg is attached to a side support at $O$ as shown in the figure. The rod is at equilibrium due to upward force $T$ acting at $P$. Assume the acceleration due to gravity as $10$ m/s$^2$. The value of $T$ is
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For rods, weight acts at center; always take torque about pivot to simplify.