Question:medium

A thin uniform rod of mass 'm' and length 'l' is suspended from one end which can oscillate in a vertical plane about the point of intersection. It is pulled to one side and then released. It passes through the equilibrium position with angular speed '$\omega$'. The kinetic energy while passing through mean position is

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Physics Tip: Be careful with the axis of rotation! If the rod were rotating about its center, $I$ would be $ml^2/12$. Since it's suspended from one end, we use $ml^2/3$.
Updated On: Apr 23, 2026
  • $ml^{2}\omega^{2}$
  • $\frac{ml^{2}\omega^{2}}{4}$
  • $\frac{ml^{2}\omega^{2}}{6}$
  • $\frac{ml^{2}\omega^{2}}{12}$
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The Correct Option is C

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