Question:medium

A thin rod has mass \(100\,g\) and length \(0.3\,m\). Find its moment of inertia about an axis passing through its centre of mass and perpendicular to its length.

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For a uniform rod: \[ I_{centre}=\frac{1}{12}ML^2, \qquad I_{end}=\frac{1}{3}ML^2. \] Always identify the axis carefully before choosing the formula.
  • \(2.5\times10^{-4}\,kg\,m^2\)
  • \(5.0\times10^{-4}\,kg\,m^2\)
  • \(7.5\times10^{-4}\,kg\,m^2\)
  • \(1.0\times10^{-3}\,kg\,m^2\)
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The Correct Option is C

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