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A thin circular ring of mass $M$ and radius $R$ is rotating about its central axis with a constant angular velocity $\omega$. Two objects, each of mass $m$, are gently attached to the opposite ends of a diameter of the ring. The new angular velocity of the ring is: [H] [width=0.5\linewidth]{85.png}

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Since angular momentum is conserved, increasing the moment of inertia must decrease the angular velocity. The ratio of new velocity to old is the inverse ratio of their moments of inertia: $\frac{M}{M+2m}$.

Updated On: May 31, 2026

$\frac{M \omega}{M + 2m}$
$\frac{(M + 2m)\omega}{M}$
$\frac{M \omega}{M + m}$
$\frac{(M - 2m)\omega}{M + 2m}$

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The Correct Option is A

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A thin circular ring of mass $M$ and radius $R$ is rotating about its central axis with a constant angular velocity $\omega$. Two objects, each of mass $m$, are gently attached to the opposite ends of a diameter of the ring. The new angular velocity of the ring is: [H] [width=0.5\linewidth]{85.png}

Show Hint

The Correct Option is A

Solution and Explanation

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