Question:medium

A tapering bar varying from the diameters from ‘d\(_1\)' to ‘d\(_2\)' and a bar of uniform cross section ‘d' have the same length and subjected to same axial pull attains the same extension. Then the ‘d' is equal to

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To remember this result easily, notice that the product of the two end diameters \( d_1 d_2 \) in the tapering bar's elongation formula simply replaces the squared diameter term \( d^2 \) from the uniform bar's formula. Setting them equal gives \( d^2 = d_1 d_2 \) instantly!
Updated On: Jul 9, 2026
  • Geometric mean of d\(_1\) and d\(_2\)
  • Arithmetic mean of d\(_1\) and d\(_2\)
  • Harmonic mean of d\(_1\) and d\(_2\)
  • Meridian of d\(_1\) and d\(_2\)
Show Solution

The Correct Option is A

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