The parallel nature of the ropes implies that the two vectors are scalar multiples. We formulate the equation: \[ 3\hat{i} + 15\hat{j} + 6\hat{k} = k(2\hat{i} + 10\hat{j} + \lambda \hat{k}) \] Component-wise equality yields: \[ 3 = 2k, \quad 15 = 10k, \quad 6 = \lambda k \] The second equation gives $k = 1.5$. Substituting this value into the third equation results in: \[ 6 = \lambda \times 1.5 \quad \Rightarrow \quad \lambda = 4 \] Consequently, $\lambda = 4$.