Step 1: Use the non-empty-subset rule. Picking at least one item from $n$ distinct items can be done in $2^n-1$ ways. Step 2: Mathematics books. $2^6-1=63$ ways from the $6$ Mathematics books. Step 3: Physics books. $2^5-1=31$ ways from the $5$ Physics books. Step 4: Chemistry books. $2^4-1=15$ ways from the $4$ Chemistry books. Step 5: Multiply the independent choices. Total $=63\times 31\times 15$. Step 6: Compute. $63\times 31=1953$ and $1953\times 15=29295$, option (1). \[ \boxed{29295} \]
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Top Questions on fundamental principle of counting