Question:medium
A steel rod of 1 m length and 10\(^{-3}\) m\(^2\) area of cross section is subjected to a linear force of 150 kN. The elongation of the rod is (Young’s modulus of steel \(1.5 \times 10^{11} \text{ Nm}^{-2}\))
A steel rod of 1 m length and 10\(^{-3}\) m\(^2\) area of cross section is subjected to a linear force of 150 kN. The elongation of the rod is (Young’s modulus of steel \(1.5 \times 10^{11} \text{ Nm}^{-2}\))
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Always simplify exponents separately from decimals. Here, the \(1.5\) cancels out immediately, leaving only powers of 10 to deal with, making the calculation very easy.
Updated On: Jun 24, 2026
- 1 cm
- 0.5 mm
- 1 m
- 1 mm
- 0.8 cm
Show Solution
The Correct Option is D
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