Question:medium

A steel pendulum clock manufactured at 32$^\circ$C and working at 47$^\circ$C is nearly (Coefficient of linear expansion of steel = $12 \times 10^{-6}$ /$^\circ$C)

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For a pendulum clock, the time lost or gained per day due to a temperature change $\Delta\theta$ can be calculated directly using the formula $\Delta t = \frac{1}{2}\alpha (\Delta\theta) \times 86400$. If the temperature increases, the clock runs slow (loses time). If the temperature decreases, it runs fast (gains time).

Updated On: Mar 30, 2026

7.8 s slow per day
7.8 s fast per day
15.6 s slow per day
15.6 s fast per day

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The Correct Option is A

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