Question:medium

A source of alternating emf $e = \varepsilon_0 \sin(\omega t)$ is connected to a pure capacitor. Then the instantaneous current in the circuit is:

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Remember the phrase "ICE" to keep your AC phases clear: In a Capacitor, I (current) comes before E (emf/voltage). Therefore, the phase inside the sine term must have a $+\frac{\pi}{2}$ shift!
Updated On: May 16, 2026
  • $I = I_0 \sin\left(\omega t + \frac{\pi}{2}\right)$
  • $I = \sqrt{2}I_0 \sin\left(\omega t + \frac{\pi}{2}\right)$
  • $I = I_0 \sin(\omega t)$
  • $I = I_0 \sin\left(\omega t - \frac{\pi}{2}\right)$
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The Correct Option is A

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