Question

A solid metallic sphere has a charge +3Q. Concentric with this sphere is a conducting spherical shell having charge -Q. The radius of the sphere is 'A' and that of the spherical shell is 'B' ($B>A$). The electric field at a distance 'R' ($A<R<B$) from the centre is ($\epsilon_{0} =$ permittivity of vacuum)

• A. $\frac{Q}{2\pi\epsilon_{0}R}$
• B. $\frac{3Q}{2\pi\epsilon_{0}R}$
• C. $\frac{3Q}{4\pi\epsilon_{0}R^{2$
• D. $\frac{4Q}{2\pi\epsilon_{0}R^{2$

Hint:

Logic Tip: Remember that the electric field inside a conducting shell due to the shell's own charge is always zero.

Answer 1

The Correct Option is C