A solid cylinder rolls down an incline without slipping. Its acceleration depends on
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For rolling without slipping,
\[
a=\frac{g\sin\theta}{1+\dfrac{I}{mR^2}}.
\]
For a solid cylinder,
\[
I=\frac12 mR^2
\]
which gives
\[
a=\frac23 g\sin\theta.
\]
Notice that the mass cancels out.