Question:medium

A solid cylinder rolls down an incline without slipping. Its acceleration depends on

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For rolling without slipping, \[ a=\frac{g\sin\theta}{1+\dfrac{I}{mR^2}}. \] For a solid cylinder, \[ I=\frac12 mR^2 \] which gives \[ a=\frac23 g\sin\theta. \] Notice that the mass cancels out.
Updated On: Jul 29, 2026
  • Only the mass of the cylinder
  • Only gravitational acceleration
  • Both the mass of the cylinder and the angle of inclination
  • Both the angle of inclination and gravitational acceleration
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The Correct Option is D

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