A short bar magnet placed with its axis at \(45^\circ\) with an external field of \(400 \times 10^{-4}\,\text{T}\) experiences a torque of \(0.024\,\text{Nm}\). If a solenoid of cross-sectional area \(10^{-4}\,\text{m}^2\) and \(500\) turns replaces the short bar magnet such that they have the same magnetic moment, then the current flowing through the solenoid is:
Show Hint
For a magnetic dipole in a uniform magnetic field, use \(\tau = MB\sin\theta\). For a solenoid, magnetic moment is \(M = NIA\).