Question

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:

• A. 0.01 mm
• B. 0.25 mm
• C. 0.5 mm
• D. 1.0 mm

Answer 1

The Correct Option is C

To find the pitch of the screw gauge, we need to understand the relationship between the least count of the screw gauge and its pitch. The least count of a screw gauge can be expressed using the formula:

\(LC = \frac{\text{Pitch}}{\text{Number of divisions on the circular scale}}\)

Here, the least count (LC) is given as 0.01 mm, and the number of divisions on the circular scale is 50. Let's use the formula to calculate the pitch.

Substitute the known values into the formula:

\(0.01 = \frac{\text{Pitch}}{50}\)

To find the pitch, multiply both sides of the equation by 50:

\(\text{Pitch} = 0.01 \times 50\)

Calculate the result:

\(\text{Pitch} = 0.50 \, \text{mm}\)

Thus, the correct pitch of the screw gauge is 0.5 mm.

Therefore, the correct answer is 0.5 mm.

Justifications for the Options:

• Option \(0.01 \, \text{mm}\): This is the least count of the screw gauge, not the pitch.
• Option \(0.25 \, \text{mm}\): Does not satisfy the least count calculation with 50 divisions when considering the given least count.
• Option \(1.0 \, \text{mm}\): This would result in a different least count, not given in the problem.