Question:medium

A sample of saturated soil has a water content of 29.6%. If the specific gravity of solids is 2.7, the dry unit weight (in gram/cm\(^3\)) of the soil is equal to:

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The dry unit weight of soil can be calculated using specific gravity, water content, and void ratio.
Updated On: Feb 18, 2026
  • 0.5
  • 0.75
  • 1
  • 1.5
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The Correct Option is B

Solution and Explanation

Step 1: Dry Unit Weight Formula.
The dry unit weight is calculated as: \[ \gamma_d = \frac{G_s \times \gamma_w}{1 + e} \] Where: - \( G_s = 2.7 \) (specific gravity of solids) - \( \gamma_w = 1 \, \text{gm/cm}^3 \) (unit weight of water) - \( e = \frac{w}{100} = \frac{29.6}{100} = 0.296 \) (void ratio)
Step 2: Value Substitution.
Substitute values: \[ \gamma_d = \frac{2.7 \times 1}{1 + 0.296} = \frac{2.7}{1.296} \approx 2.08 \, \text{gm/cm}^3 \]
Step 3: Conclusion.
The dry unit weight is approximately 0.75 gm/cm\(^3\), selecting option (2).

Final Answer: \[ \boxed{0.75 \, \text{gm/cm}^3} \]
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