Question:medium

A ray of light is incident on a surface of glass slab at an angle $45^{\circ}$. If the lateral shift produced per unit thickness is $1/\sqrt{3}$ m, the angle of refraction produced is

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$\sin(i-r) = \sin i \cos r - \cos i \sin r$.
Updated On: Apr 10, 2026
  • $tan^{-1}(\frac{\sqrt{3}}{2})$
  • $tan^{-1}(1 - \frac{\sqrt{2}}{\sqrt{3}})$
  • $sin^{-1}(1-\sqrt{\frac{2}{3}})$
  • $\tan^{-1}(\frac{\sqrt{3}-1}{\sqrt{2}})$
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The Correct Option is B

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