To determine the wavelength bandwidth corresponding to a frequency bandwidth of 6 MHz to 10 MHz, we need to understand the relationship between frequency and wavelength. This relationship is given by the formula:
\(c = \lambda \cdot f\)
where:
First, convert the given frequencies from MHz (megahertz) to Hz (hertz):
Using the formula, calculate the corresponding wavelengths:
The wavelength bandwidth is the difference between the two wavelengths:
Therefore, the correct answer is 20 m, which corresponds to the wavelength bandwidth between the given frequency range.
Match List-I with List-II:
| List-I (Modulation Schemes) | List-II (Wave Expressions) |
|---|---|
| (A) Amplitude Modulation | (I) \( x(t) = A\cos(\omega_c t + k m(t)) \) |
| (B) Phase Modulation | (II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \) |
| (C) Frequency Modulation | (III) \( x(t) = A + m(t)\cos(\omega_c t) \) |
| (D) DSB-SC Modulation | (IV) \( x(t) = m(t)\cos(\omega_c t) \) |
Choose the correct answer: