A radio antenna receiver works at \((10.5 \pm 4.5)\,MHz\) with an effective bandwidth of \(9\,MHz\). The corresponding wavelength bandwidth is:

Question

The percentage of the total power carried by the sidebands of the AM wave for tone modulation when the modulation index is 0.3 is:

Answer 1

Step 1: Frequency band extremes.
f_min = 10.5 - 4.5 = 6 MHz; f_max = 10.5 + 4.5 = 15 MHz.

Step 2: Wavelength conversion.
λ = c/f.

Step 3: Extreme wavelengths.
λ_max = 3×10⁸/6×10⁶ = 50 m; λ_min = 3×10⁸/15×10⁶ = 20 m.

Step 4: Bandwidth in wavelength.
Δλ = 50 - 20 = 30 m.

Step 5: Conclusion.
The wavelength bandwidth is 30 m.

List-I (Modulation Schemes)	List-II (Wave Expressions)
(A) Amplitude Modulation	(I) \( x(t) = A\cos(\omega_c t + k m(t)) \)
(B) Phase Modulation	(II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \)
(C) Frequency Modulation	(III) \( x(t) = A + m(t)\cos(\omega_c t) \)
(D) DSB-SC Modulation	(IV) \( x(t) = m(t)\cos(\omega_c t) \)

A radio antenna receiver works at \((10.5 \pm 4.5)\,MHz\) with an effective bandwidth of \(9\,MHz\). The corresponding wavelength bandwidth is:

Show Hint

The Correct Option is B

Solution and Explanation

Top Questions on communication systems

Questions Asked in AP EAPCET exam