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A pure inductor of self inductance 500 mH is connected to an alternating voltage supply of \(100\sqrt{2}\pi \sin 100\pi t\) volt. The current in the circuit in ampere is
A pure inductor of self inductance 500 mH is connected to an alternating voltage supply of \(100\sqrt{2}\pi \sin 100\pi t\) volt. The current in the circuit in ampere is
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In AC circuits, unless "peak" or "instantaneous" is mentioned, "current" or "voltage" always refers to the RMS value. Be careful with \(\pi\) in the numerator and denominator; they usually cancel out in textbook problems.
Updated On: Jun 24, 2026
- \(\sqrt{2}\)
- 5
- \(5\sqrt{2}\)
- \(2\sqrt{2}\)
- 2
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The Correct Option is
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