A positive integer $m$ is increased by 20% and the resulting number is 1080. Then the integer $m$ is
To solve the problem, we need to find the original integer \( m \) that, when increased by 20%, results in 1080.
The increased number is 20% more than \( m \), which can be expressed as:
\(m + \frac{20}{100} \times m = 1080\)
\(m + 0.2m = 1080\)
\(1.2m = 1080\)
\(m = \frac{1080}{1.2}\)
\(m = 900\)
Thus, the integer \( m \) is 900.
Explanation of Why 900 is Correct:
\(900 + 0.2 \times 900 = 900 + 180 = 1080\)