Question:medium

A physicist works in a laboratory where the magnetic field is 2 T. She wears a necklace enclosing area 0.01 m\(^2\) in such a way that the plane of the necklace is normal to the field and is having a resistance \(R = 0.01\ \Omega\). Because of power failure, the field decays to 1 T in time \(10^{-3}\) s. Then what is the total heat produced in her necklace?

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Heat equals energy dissipated in resistance due to induced current.
Updated On: Jun 16, 2026
  • 10 J
  • 20 J
  • 30 J
  • 40 J
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The Correct Option is A

Solution and Explanation

To determine the total heat produced in the necklace, we can use the principles of electromagnetic induction. According to Faraday's Law, a changing magnetic field through a loop induces an electromotive force (emf) in the circuit. This emf leads to a current through the resistive material, generating heat.

  1. \(E = -\frac{{d\Phi}}{{dt}}\): Calculate the induced emf (E).

The magnetic flux (\(\Phi\)) through the necklace enclosed area can be expressed as:

The formula for magnetic flux is:

\(\Phi = B \times A\)

  • Where \(B\) is the magnetic field, and \(A\) is the area.

Initially, before the power failure:

\(\Phi_{\text{initial}} = 2 \, \text{T} \times 0.01 \, \text{m}^2 = 0.02 \, \text{Wb}\)

After the power failure, the field drops to 1T:

\(\Phi_{\text{final}} = 1 \, \text{T} \times 0.01 \, \text{m}^2 = 0.01 \, \text{Wb}\)

The change in magnetic flux is:

\(\Delta \Phi = \Phi_{\text{final}} - \Phi_{\text{initial}} = 0.01 \, \text{Wb} - 0.02 \, \text{Wb} = -0.01 \, \text{Wb}\)

Since the time \(\Delta t = 10^{-3} \, s\), the induced emf is:

\(E = -\frac{{\Delta \Phi}}{{\Delta t}} = -\frac{{-0.01 \, \text{Wb}}}{{10^{-3} \, s}} = 10 \, \text{V}\)

  1. Calculate the heat produced using: \(H = \frac{{E^2 \times t}}{{R}}\).

Where \(E\) is the emf, \(R\) is the resistance, and \(t\) is the time duration.

Substitute values:

\(H = \frac{{(10 \, \text{V})^2 \times 10^{-3} \, \text{s}}}{{0.01 \, \Omega}} = \frac{{100 \, \text{V}^2 \times 10^{-3} \, \text{s}}}{{0.01 \, \Omega}}\)

Simplifying:

\(H = \frac{{100 \times 10^{-3}}}{{0.01}} = 10 \, \text{J}\)

The total heat produced in her necklace is 10 J.

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