Question:medium

A physical quantity is represented by $P = X^aY^bZ^c$. If the errors in the measurements of the physical quantities X, Y and Z are respectively a%, b% and c%, then the percentage error in the determination of quantity P is

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The variable names for the percentage errors ($a, b, c$) happen to be the same as the exponents in this specific problem. Don't get confused! Usually, the formula is: $%P = (\text{power}_x)(%x) + (\text{power}_y)(%y) + \dots$ Here, power is 'a' and error is 'a', so we get $a \cdot a = a^2$.
Updated On: Mar 31, 2026
  • $a^2+b^2+c^2$
  • $a+b+c$
  • $a^2+b^2-c^2$
  • $a+b-c$
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The Correct Option is A

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