Question:medium

A perpendicular is drawn from the point P(2, 4, -1) to the line \(\frac{x + 5}{1} = \frac{y + 3}{4} = \frac{z - 6}{-9}\). The equation of the perpendicular from P to the given line is

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Foot of perpendicular is obtained by projecting point onto line.

Updated On: Apr 7, 2026

\(\frac{x - 2}{6} = \frac{y - 4}{3} = \frac{z + 1}{2}\)
\(\frac{x + 2}{6} = \frac{y - 4}{3} = \frac{z + 1}{2}\)
\(\frac{x + 2}{-6} = \frac{y - 4}{3} = \frac{z + 1}{2}\)
\(\frac{x + 2}{6} = \frac{y + 4}{3} = \frac{z + 1}{2}\)

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The Correct Option is A

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Questions Asked in MET exam

If \(f(x) = \begin{cases} x, & 0 \le x \le 1 \\ 2x - 1, & 1<x \end{cases}\), then

MET - 2019
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