Question:medium

A particle is projected vertically upward with an initial velocity of $ 20 \, m/s $. Calculate the maximum height reached by the particle.

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Tip: At maximum height, velocity becomes zero. Use appropriate kinematic formulas accordingly.
Updated On: Nov 26, 2025
  • \(20 \, m\)
  • \(15 \, m\)
  • \(10 \, m\)
  • \(25 \, m\)
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The Correct Option is A

Solution and Explanation

Step 1: Identify known parameters
Initial velocity, \( u = 20 \, m/s \)
Final velocity at peak altitude, \( v = 0 \, m/s \)
Gravitational acceleration, \( g = 9.8 \, m/s^2 \) (acting downwards)

Step 2: Select appropriate kinematic formula
\[ v^2 = u^2 - 2gh \] Here, \( h \) represents the maximum altitude.

Step 3: Insert values and compute \( h \)
\[ 0 = (20)^2 - 2 \times 9.8 \times h \implies 400 = 19.6h \implies h = \frac{400}{19.6} \approx 20.41 \, m \]

Step 4: State the conclusive result
Approximated to the nearest option: \( h = 20 \, m \).

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