Question:medium

A parallel plate capacitor of capacitance \(1\ \mu\text{F}\) is charged to a potential difference of \(20\ \text{V}\). The distance between plates is \(1\ \mu\text{m}\). The energy density between plates of capacitor is:

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For capacitor energy density, first calculate \(E=\frac{V}{d}\), then use \(u=\frac{1}{2}\varepsilon_0E^2\).
Updated On: May 15, 2026
  • \(1.8\times 10^3\ \text{J/m}^3\)
  • \(2\times 10^3\ \text{J/m}^3\)
  • \(2\times 10^2\ \text{J/m}^3\)
  • \(1.8\times 10^5\ \text{J/m}^3\)
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The Correct Option is A

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