Question:medium

A body of $20\text{ g}$ and $+50\ \mu\text{C}$ charge is suspended from the ceiling by a string. If a horizontal electric field of $10\text{ kV/m}$ is applied, the angle between the string and vertical direction is: (Take $g = 10\text{ N/kg}$)

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For any particle in a horizontal field, the angle $\theta$ is always determined by the ratio of the horizontal force to the vertical force: $\tan\theta = F_h / F_v$.
Updated On: May 13, 2026
  • $\tan^{-1}(2.50)$
  • $\tan^{-1}(3.00)$
  • $\tan^{-1}(3.50)$
  • $\sin^{-1}(2.50)$
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The Correct Option is A

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