Question

A pair of fair dice is rolled. What is the probability that the second die lands on a higher value than the first?

• A. \(\frac{1}{36}\)
• B. \(\frac{5}{36}\)
• C. \(\frac{1}{6}\)
• D. \(\frac{5}{12}\)
• E.

Hint:

By symmetry, \(P(y > x) = P(x > y)\). Since there are 6 outcomes where \(x = y\), the number of outcomes where \(x \neq y\) is \(36 - 6 = 30\). Thus, \(P(y > x) = \frac{30/2}{36} = \frac{15}{36} = \frac{5}{12}\).

Answer 1

The Correct Option is D