A number is first increased by 20% and the result is then decreased by 20%. The final value is what percent of the original?

Question

A bought a phone from a store and paid \(\frac{1}{6}\) of the price using UPI, \(\frac{1}{3}\) of the price in cash, and the remaining balance a year later. He also paid 10% interest on the remaining balance after one year. What was the original price of the phone?

Answer 1

Step 1: Successive change factor \(= 1.20 \times 0.80 = 0.96\).
Step 2: So the final value is \(96\%\) of the original, a net \(4\%\) fall.

Quick Tip: Equal up-then-down changes of \(x\%\) always leave a net fall of \(\dfrac{x^2}{100}\%\).

A number is first increased by 20% and the result is then decreased by 20%. The final value is what percent of the original?

The Correct Option is B

Solution and Explanation

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