The given nuclear reaction can be analyzed as follows:
The reaction is:
_{Z}^{A}\textrm{X} \rightarrow _{Z+1}^{A}\textrm{Y} + _{-1}^{0}\textrm{e}
+ \bar{\nu}
Here,:
- _{Z}^{A}\textrm{X} represents the parent nucleus
- _{Z+1}^{A}\textrm{Y} represents the daughter nucleus
- _{-1}^{0}\textrm{e} represents a beta particle (electron)
- \bar{\nu} represents an antineutrino
The reaction involves the conversion of a neutron into a proton within the nucleus, which results in the emission of a beta particle and an antineutrino. This process is known as \beta-decay.
Let's consider the options:
- \beta-decay: This is consistent with the nuclear reaction shown, where a neutron is converted into a proton, emitting a beta particle (electron) and an antineutrino.
- \gamma-decay: Involves the emission of a gamma photon without changing the number of protons or neutrons, which doesn't match the reaction given.
- Fusion: Involves combining two light nuclei to form a heavier nucleus, which is not represented here.
- Fission: Involves splitting a heavy nucleus into two lighter nuclei, which also doesn't match this reaction.
Thus, the given nuclear reaction represents \beta-decay. The correct answer is \beta-decay.